4G/LTE - BL/CE |
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HARQ
In short, HARQ mechanism for LTE M1 downlink is similar to legacy LTE mechanism (except the repetitive transmission), but HARQ mechanism is a little bit different from legacy LTE as described below.
HARQ Process for Downlink is similar to legacy LTE except that each transmission would happen in repetition in LTE-M1. The rough HARQ sequence would be as follows. i) UE <-- NW : MPDCCH (DCI for PDCCH) in repetition ii) UE <-- NW : PDSCH in repetition iii) UE --> NW : HARQ ACK/NACK Note : Step i) and ii) happens not in the same subframe. (This is different from legacy LTE) Following is what is commented in 3GPP
36.321 - 5.3.2.1 HARQ entity describes as follows
HARQ Process for Downlink of M1 is similar to legacy LTE except that each transmission would happen in repetition. However, HARQ Process for Uplink in M1 is different from legacy LTE. The most critical difference is that eNB does not send any HARQ ACK/NACK for PUSCH (It is understandable because there is no PHICH in LTE M1). Then, you may ask how eNB can handle the case where PUSCH reception fail ? Following process would give you the answer.
The rough HARQ sequence would be as follows.
i) UE <-- NW : MPDCCH (DCI for PUSCH) with UL Grant in repetition ii) UE --> NW : PUSCH in repetition iii) One of the following cases happens : NOTE : If UE does not receive MPDCCH for PUSCH retransmission, UE assumes that PUSCH is properly received by NW. PHICH does not exists to send ACK/NACK for PUSCH in LTE M1.
36.321 - 5.4.2.1 HARQ entity, 5.4.2.2 HARQ process, 7.7 HARQ RTT Timers describes as follows
RV Determination : PDSCH for SystemInformationBlockType1-BR
SystemInformationBlockType1-BR is retransmitted and each retransmission uses different RV (Redundancy Version). RV for each retransmission varies depending on SystemInformationBlockType1-BR retransmission patter as described below : (Refer to 36.321 - 5.3.1 DL Assignment reception for further details) RV = ceiling(3/2*k) mod 4 // k is determined depending of the number of repetitions Case 1 : number of repetitions for PDSCH carrying SystemInformationBlockType1-BR is 4 k = floor(SFN/2) mod 4 Case 2 : number of repetitions for PDSCH carrying SystemInformationBlockType1-BR is 8 k = SFN mod 4 Case 3 : number of repetitions for PDSCH carrying SystemInformationBlockType1-BR is 16 k = (SFN * 10 + i) mod 4 , where i = subframe number in the SFN
[1] 3GPP TS 36.321 V13.2.0 (2016-06)
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